{"id":24146,"date":"2026-09-29T05:22:31","date_gmt":"2026-09-29T05:22:31","guid":{"rendered":"https:\/\/www.examlabs.com\/certification\/?p=24146"},"modified":"2026-09-29T05:22:31","modified_gmt":"2026-09-29T05:22:31","slug":"huawei-h13-611-practice-test-questions-and-exam-dumps-part10-q181-200","status":"publish","type":"post","link":"https:\/\/www.examlabs.com\/certification\/huawei-h13-611-practice-test-questions-and-exam-dumps-part10-q181-200\/","title":{"rendered":"Huawei H13-611 Practice Test Questions and Exam Dumps Part10 Q181-200"},"content":{"rendered":"

View Full <\/b>Huawei H13-611 Exam Dumps<\/b><\/a> and Practice Test Dumps.<\/b><\/p>\n


\n<\/b>Q181. Which mechanism keeps controller cache data consistent between redundant controllers<\/b><\/p>\n

    \n
  1. <\/b> Disk zoning<\/span><\/li>\n
  2. <\/b> Host scanning<\/span><\/li>\n
  3. <\/b> Cache mirroring<\/span><\/li>\n
  4. <\/b> File sharing<\/span><\/li>\n<\/ol>\n

    Correct Answer: 3. Cache mirroring<\/b><\/p>\n

    Explanation:<\/b><\/p>\n

    Cache mirroring keeps important write data synchronized between redundant storage controllers. When one controller accepts data into protected cache, another controller can maintain a corresponding copy so information remains available if the first controller fails. This supports high availability and reduces the risk of losing acknowledged write operations. Disk zoning is not used to synchronize controller cache. Host scanning discovers available storage resources. File sharing provides access to network files. Cache mirroring is therefore the correct answer because it specifically protects cached data across controllers and helps storage services continue safely when a controller experiences an unexpected failure.<\/span><\/p>\n

    Q182. Which feature predicts disk problems before complete failure occurs<\/b><\/p>\n

      \n
    1. <\/b> SMART monitoring<\/span><\/li>\n
    2. <\/b> LUN mapping<\/span><\/li>\n
    3. <\/b> Compression<\/span><\/li>\n
    4. <\/b> File locking<\/span><\/li>\n<\/ol>\n

      Correct Answer: 1. SMART monitoring<\/b><\/p>\n

      Explanation:<\/b><\/p>\n

      SMART monitoring examines drive health indicators and can identify conditions that suggest a disk may fail in the future. Information such as error counts, operating conditions, and other device statistics can help storage systems generate early warnings. Administrators can then replace a risky drive before a complete failure occurs. LUN mapping presents logical storage to hosts. Compression reduces storage consumption. File locking controls access to files. SMART monitoring is therefore the correct answer because it focuses on predictive disk health information and helps administrators take preventive action before a physical drive becomes completely unavailable.<\/span><\/p>\n

      Q183. Which process returns storage ownership to the preferred controller after recovery<\/b><\/p>\n

        \n
      1. <\/b> Formatting<\/span><\/li>\n
      2. <\/b> Replication<\/span><\/li>\n
      3. <\/b> Deduplication<\/span><\/li>\n
      4. <\/b> Failback<\/span><\/li>\n<\/ol>\n

        Correct Answer: 4. Failback<\/b><\/p>\n

        Explanation:<\/b><\/p>\n

        Failback returns storage services or resource ownership to the preferred controller after the original fault has been corrected. During a failure, another controller may temporarily take over storage processing through failover. Once the affected controller is healthy again, administrators can restore the normal operating arrangement. Formatting prepares storage for use. Replication maintains additional data copies. Deduplication reduces duplicate information. Failback is therefore the correct answer because it specifically describes returning services from a temporary recovery state to the intended controller after normal system conditions have been restored and verified.<\/span><\/p>\n

        Q184. Which host feature allows a server to start its operating system from SAN storage<\/b><\/p>\n

          \n
        1. <\/b> File quota<\/span><\/li>\n
        2. <\/b> SAN boot<\/span><\/li>\n
        3. <\/b> Cache flush<\/span><\/li>\n
        4. <\/b> Object lock<\/span><\/li>\n<\/ol>\n

          Correct Answer: 2. SAN boot<\/b><\/p>\n

          Explanation:<\/b><\/p>\n

          SAN boot allows a server to start its operating system from a logical disk located on shared storage rather than from a local drive. This can simplify server replacement and centralized storage management because operating system volumes are maintained on the storage area network. Proper host adapter configuration and storage access must be available during the boot process. File quota controls user capacity. Cache flush commits cached writes to storage. Object lock protects retained information. SAN boot is therefore the correct answer because it specifically enables a host to load its operating system from remotely presented block storage.<\/span><\/p>\n

          Q185. Which RAID characteristic causes extra writes when parity must be updated<\/b><\/p>\n

            \n
          1. <\/b> Write penalty<\/span><\/li>\n
          2. <\/b> Read cache<\/span><\/li>\n
          3. <\/b> Host masking<\/span><\/li>\n
          4. <\/b> Port login<\/span><\/li>\n<\/ol>\n

            Correct Answer: 1. Write penalty<\/b><\/p>\n

            Explanation:<\/b><\/p>\n

            Write penalty refers to the additional storage operations required when a RAID level must calculate and update parity information during write activity. Parity based RAID can require extra reads and writes compared with simple striping or some mirrored configurations. This can affect performance for workloads with heavy write activity. Read cache improves access to frequently requested data. Host masking controls LUN visibility. Port login establishes network communication. Write penalty is therefore the correct answer because it describes the additional input and output work created by parity protection when data is modified within certain RAID configurations.<\/span><\/p>\n

            Q186. Which hardware capability allows a failed drive to be replaced while the system remains powered<\/b><\/p>\n

              \n
            1. <\/b> Compression<\/span><\/li>\n
            2. <\/b> Archiving<\/span><\/li>\n
            3. <\/b> Cloning<\/span><\/li>\n
            4. <\/b> Hot swap**<\/span><\/li>\n<\/ol>\n

              Correct Answer: 4. Hot swap<\/b><\/p>\n

              Explanation:<\/b><\/p>\n

              Hot swap capability allows administrators to remove and replace supported hardware components while the storage system remains powered and operational. Disk drives are common examples of hot swappable components in enterprise storage systems. This reduces downtime because the entire system does not need to be shut down for routine replacement. Compression reduces data size. Archiving moves inactive information to long term storage. Cloning creates another usable data copy. Hot swap is therefore the correct answer because it specifically supports component replacement during normal system operation when redundancy and maintenance procedures allow the change to be performed safely.<\/span><\/p>\n

              Q187. Which controller state indicates that it is currently serving storage traffic<\/b><\/p>\n

                \n
              1. <\/b> Offline<\/span><\/li>\n
              2. <\/b> Standby only<\/span><\/li>\n
              3. <\/b> Active<\/span><\/li>\n
              4. <\/b> Removed<\/span><\/li>\n<\/ol>\n

                Correct Answer: 3. Active<\/b><\/p>\n

                Explanation:<\/b><\/p>\n

                An active controller is currently processing storage input and output requests and providing services to connected hosts. In systems with multiple controllers, workload ownership may be distributed so that several controllers actively handle storage traffic. Offline or removed controllers cannot provide normal service. A standby controller may be available for recovery but may not currently own active workloads depending on the architecture. Active is therefore the correct answer because it directly describes a controller that is presently handling storage operations and participating in normal data service delivery within the storage system.<\/span><\/p>\n

                Q188. Which practice should be completed before moving production data to new storage<\/b><\/p>\n

                  \n
                1. <\/b> Delete all logs<\/span><\/li>\n
                2. <\/b> Migration planning<\/span><\/li>\n
                3. <\/b> Disable monitoring<\/span><\/li>\n
                4. <\/b> Remove redundancy<\/span><\/li>\n<\/ol>\n

                  Correct Answer: 2. Migration planning<\/b><\/p>\n

                  Explanation:<\/b><\/p>\n

                  Migration planning should be completed before production data is moved to a new storage system or resource. Administrators should identify applications, dependencies, capacity requirements, connectivity, downtime limits, validation steps, and rollback procedures. Good planning reduces the risk of service interruption or data loss during the migration. Deleting logs removes useful information. Disabling monitoring reduces visibility into the environment. Removing redundancy increases risk. Migration planning is therefore the correct answer because it prepares the technical and operational steps required to transfer production workloads safely and verify that applications work correctly after the move is complete.<\/span><\/p>\n

                  Q189. Which mechanism helps a host select the optimized path to a storage controller<\/b><\/p>\n

                    \n
                  1. <\/b> NFS export<\/span><\/li>\n
                  2. <\/b> File quota<\/span><\/li>\n
                  3. <\/b> Cache compression<\/span><\/li>\n
                  4. <\/b> ALUA<\/span><\/li>\n<\/ol>\n

                    Correct Answer: 4. ALUA<\/b><\/p>\n

                    Explanation:<\/b><\/p>\n

                    ALUA provides information about path states so a host can identify which paths are optimized for accessing a storage resource. In multipath environments, some paths may provide more direct access through the controller that currently owns or prefers the LUN. Host multipathing software can use ALUA information to select efficient paths and improve failover behavior. NFS export provides shared file access. File quota controls capacity usage. Cache compression is unrelated to path selection. ALUA is therefore the correct answer because it helps hosts distinguish optimized and nonoptimized storage paths when using redundant controller connections.<\/span><\/p>\n

                    Q190. Which value is most useful for identifying a sudden increase in storage response delay<\/b><\/p>\n

                      \n
                    1. <\/b> Latency trend<\/span><\/li>\n
                    2. <\/b> Total capacity<\/span><\/li>\n
                    3. <\/b> User count<\/span><\/li>\n
                    4. <\/b> Drive label<\/span><\/li>\n<\/ol>\n

                      Correct Answer: 1. Latency trend<\/b><\/p>\n

                      Explanation:<\/b><\/p>\n

                      A latency trend shows how storage response time changes over a period and can reveal sudden or gradual performance problems. If latency rises sharply, administrators can investigate controller load, disk activity, network paths, or application behavior. Total capacity indicates how much storage exists but does not directly show response delay. User count may provide context but is not the primary performance measurement. Drive labels identify hardware. Latency trend is therefore the correct answer because it directly tracks how long storage requests take and helps administrators identify when response performance becomes worse than normal operating conditions.<\/span><\/p>\n

                      Q191. Which feature reserves resources for an important workload when several applications share storage<\/b><\/p>\n

                        \n
                      1. <\/b> File rename<\/span><\/li>\n
                      2. <\/b> Resource partitioning<\/span><\/li>\n
                      3. <\/b> Tape export<\/span><\/li>\n
                      4. <\/b> Disk formatting<\/span><\/li>\n<\/ol>\n

                        Correct Answer: 2. Resource partitioning<\/b><\/p>\n

                        Explanation:<\/b><\/p>\n

                        Resource partitioning allows selected storage resources to be reserved or controlled for specific workloads. This can help important applications receive predictable performance when several systems compete for shared cache, processing capability, or other storage resources. File renaming changes only a file name. Tape export moves backup media or data. Disk formatting prepares a storage resource for use. Resource partitioning is therefore the correct answer because it separates or assigns portions of shared resources according to workload requirements. This can reduce interference between applications and help maintain service levels for important production systems.<\/span><\/p>\n

                        Q192. Which process checks the health of storage components after system startup<\/b><\/p>\n

                          \n
                        1. <\/b> Replication<\/span><\/li>\n
                        2. <\/b> Deduplication<\/span><\/li>\n
                        3. <\/b> Self test<\/span><\/li>\n
                        4. <\/b> Thin provisioning<\/span><\/li>\n<\/ol>\n

                          Correct Answer: 3. Self test<\/b><\/p>\n

                          Explanation:<\/b><\/p>\n

                          A self test checks hardware and system components to determine whether they are operating correctly. Storage systems can perform diagnostic checks during startup or maintenance to identify problems with controllers, memory, drives, interfaces, or other components. Replication maintains another data copy. Deduplication removes repeated information. Thin provisioning improves capacity allocation efficiency. Self test is therefore the correct answer because it directly examines system health and helps identify faults before normal production services depend on the affected components. Diagnostic testing is an important part of maintaining reliable storage hardware and reducing unexpected service interruptions.<\/span><\/p>\n

                          Q193. Which action reduces risk before updating storage system software<\/b><\/p>\n

                            \n
                          1. <\/b> Verify system health<\/span><\/li>\n
                          2. <\/b> Remove spare drives<\/span><\/li>\n
                          3. <\/b> Disable redundancy<\/span><\/li>\n
                          4. <\/b> Delete configuration records<\/span><\/li>\n<\/ol>\n

                            Correct Answer: 1. Verify system health<\/b><\/p>\n

                            Explanation:<\/b><\/p>\n

                            Verifying system health before a software update helps ensure that controllers, disks, paths, power components, and other critical resources are operating normally. Performing an update while the system already has unresolved faults can increase the chance of service interruption or unsuccessful maintenance. Administrators should also review procedures and protect important configuration information. Removing spare drives and disabling redundancy increase risk. Deleting configuration records removes useful recovery information. Verify system health is therefore the correct answer because maintenance should begin from a stable system state with known faults resolved or properly evaluated before software changes are introduced.<\/span><\/p>\n

                            Q194. Which technology can move a virtual machine disk between storage resources while service continues<\/b><\/p>\n

                              \n
                            1. <\/b> Tape rotation<\/span><\/li>\n
                            2. <\/b> File locking<\/span><\/li>\n
                            3. <\/b> Disk scrubbing<\/span><\/li>\n
                            4. <\/b> Online migration<\/span><\/li>\n<\/ol>\n

                              Correct Answer: 4. Online migration<\/b><\/p>\n

                              Explanation:<\/b><\/p>\n

                              Online migration moves active data or virtual machine storage from one resource to another while minimizing or avoiding service interruption. This capability is useful during storage upgrades, load balancing, maintenance, or capacity changes. Tape rotation manages backup media. File locking controls simultaneous access to files. Disk scrubbing checks storage media for hidden errors. Online migration is therefore the correct answer because it specifically supports movement of active workloads while applications continue operating. Careful planning is still required to confirm performance, compatibility, connectivity, and data consistency throughout the migration process and after the new storage location becomes active.<\/span><\/p>\n

                              Q195. Which value indicates whether a storage port is close to its maximum transfer capability<\/b><\/p>\n

                                \n
                              1. <\/b> Recovery point<\/span><\/li>\n
                              2. <\/b> Port utilization<\/span><\/li>\n
                              3. <\/b> File count<\/span><\/li>\n
                              4. <\/b> Retention period<\/span><\/li>\n<\/ol>\n

                                Correct Answer: 2. Port utilization<\/b><\/p>\n

                                Explanation:<\/b><\/p>\n

                                Port utilization shows how much of a storage interface capacity is currently being consumed. High utilization over long periods may indicate that a port is approaching its available bandwidth limit and could become a performance bottleneck. Recovery point relates to data protection. File count measures the number of stored files but does not directly describe network load. Retention period defines how long information must remain protected. Port utilization is therefore the correct answer because it helps administrators understand whether a storage network interface has sufficient remaining capacity to handle current and future application traffic without becoming overloaded.<\/span><\/p>\n

                                Q196. Which maintenance action should follow replacement of a failed power supply<\/b><\/p>\n

                                  \n
                                1. <\/b> Delete storage pools<\/span><\/li>\n
                                2. <\/b> Disable alarms<\/span><\/li>\n
                                3. <\/b> Verify power redundancy<\/span><\/li>\n
                                4. <\/b> Remove host mappings<\/span><\/li>\n<\/ol>\n

                                  Correct Answer: 3. Verify power redundancy<\/b><\/p>\n

                                  Explanation:<\/b><\/p>\n

                                  After replacing a failed power supply, administrators should verify that the new component is healthy and that power redundancy has been restored. System alarms should also be checked to confirm that no related faults remain. Deleting storage pools would destroy logical storage resources. Disabling alarms reduces visibility into system conditions. Removing host mappings would unnecessarily interrupt storage access. Verify power redundancy is therefore the correct answer because maintenance is not complete until the replacement component is operating normally and the system has regained the expected level of protection against another power supply failure.<\/span><\/p>\n

                                  Q197. Which storage method keeps frequently used data on faster media and inactive data on slower media<\/b><\/p>\n

                                    \n
                                  1. <\/b> Formatting<\/span><\/li>\n
                                  2. <\/b> Mirroring<\/span><\/li>\n
                                  3. <\/b> Cloning<\/span><\/li>\n
                                  4. <\/b> Tiered storage**<\/span><\/li>\n<\/ol>\n

                                    Correct Answer: 4. Tiered storage<\/b><\/p>\n

                                    Explanation:<\/b><\/p>\n

                                    Tiered storage places data on different classes of media according to performance needs and access frequency. Frequently accessed information can be stored on faster flash media while inactive or less critical data remains on lower cost storage. This provides a balance between performance and capacity cost. Formatting prepares storage for use. Mirroring creates duplicate copies. Cloning creates another usable data copy. Tiered storage is therefore the correct answer because it organizes information according to workload characteristics and allows expensive high performance media to be focused on data that benefits most from faster access.<\/span><\/p>\n

                                    Q198. Which document helps administrators return to the previous configuration if a change fails<\/b><\/p>\n

                                      \n
                                    1. <\/b> Rollback plan<\/span><\/li>\n
                                    2. <\/b> Capacity alarm<\/span><\/li>\n
                                    3. <\/b> Drive label<\/span><\/li>\n
                                    4. <\/b> User quota<\/span><\/li>\n<\/ol>\n

                                      Correct Answer: 1. Rollback plan<\/b><\/p>\n

                                      Explanation:<\/b><\/p>\n

                                      A rollback plan describes the steps required to restore the previous working configuration if a planned change causes unexpected problems. It should be prepared before major maintenance, migration, software upgrades, or configuration changes. A clear rollback plan reduces downtime because administrators already know how to reverse the change safely. A capacity alarm warns about storage usage. A drive label identifies hardware. A user quota limits storage consumption. Rollback plan is therefore the correct answer because it provides a predefined recovery path when a storage change does not produce the expected result and normal services need to be restored quickly.<\/span><\/p>\n

                                      Q199. Which condition means a storage path is available but is not currently the preferred route<\/b><\/p>\n

                                        \n
                                      1. <\/b> Failed<\/span><\/li>\n
                                      2. <\/b> Optimized<\/span><\/li>\n
                                      3. <\/b> Nonoptimized<\/span><\/li>\n
                                      4. <\/b> Removed<\/span><\/li>\n<\/ol>\n

                                        Correct Answer: 3. Nonoptimized<\/b><\/p>\n

                                        Explanation:<\/b><\/p>\n

                                        A nonoptimized path is available for storage access but is not the preferred route to the resource. In redundant controller environments, the path may still work but can involve an indirect route through another controller. Multipath software can prefer optimized paths during normal operation and use nonoptimized paths when required. A failed path cannot carry storage traffic. An optimized path is normally preferred. A removed path is no longer available. Nonoptimized is therefore the correct answer because it describes a usable path that provides access but is not currently considered the most efficient route to the storage resource.<\/span><\/p>\n

                                        Q200. Which practice compares current storage performance with normal historical behavior<\/b><\/p>\n

                                          \n
                                        1. <\/b> Formatting<\/span><\/li>\n
                                        2. <\/b> Baseline analysis<\/span><\/li>\n
                                        3. <\/b> LUN deletion<\/span><\/li>\n
                                        4. <\/b> File archiving<\/span><\/li>\n<\/ol>\n

                                          Correct Answer: 2. Baseline analysis<\/b><\/p>\n

                                          Explanation:<\/b><\/p>\n

                                          Baseline analysis compares current storage performance with previously recorded normal operating behavior. Administrators can establish typical values for latency, throughput, IOPS, utilization, and other measurements. When current performance differs significantly from the baseline, the change can help identify developing problems or unusual workload activity. Formatting prepares storage for use. LUN deletion removes logical storage resources. File archiving moves inactive data for long term retention. Baseline analysis is therefore the correct answer because it provides a reference for determining whether current storage behavior is normal and supports more effective performance monitoring and troubleshooting.<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"

                                          View Full Huawei H13-611 Exam Dumps and Practice Test Dumps. Q181. Which mechanism keeps controller cache data consistent between redundant controllers Disk zoning Host scanning Cache mirroring File sharing Correct Answer: 3. Cache mirroring Explanation: Cache mirroring keeps important write data synchronized between redundant storage controllers. When one controller accepts data into protected cache, another […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[1648,1647],"tags":[],"_links":{"self":[{"href":"https:\/\/www.examlabs.com\/certification\/wp-json\/wp\/v2\/posts\/24146"}],"collection":[{"href":"https:\/\/www.examlabs.com\/certification\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.examlabs.com\/certification\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.examlabs.com\/certification\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.examlabs.com\/certification\/wp-json\/wp\/v2\/comments?post=24146"}],"version-history":[{"count":1,"href":"https:\/\/www.examlabs.com\/certification\/wp-json\/wp\/v2\/posts\/24146\/revisions"}],"predecessor-version":[{"id":24147,"href":"https:\/\/www.examlabs.com\/certification\/wp-json\/wp\/v2\/posts\/24146\/revisions\/24147"}],"wp:attachment":[{"href":"https:\/\/www.examlabs.com\/certification\/wp-json\/wp\/v2\/media?parent=24146"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.examlabs.com\/certification\/wp-json\/wp\/v2\/categories?post=24146"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.examlabs.com\/certification\/wp-json\/wp\/v2\/tags?post=24146"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}