Databricks Certified Associate Developer for Apache Spark Practice Test Questions and Exam Dumps Part12 Q221-240

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Question 221.

A developer joins a very large DataFrame with a small lookup DataFrame that can comfortably fit in executor memory. Which technique can reduce shuffle overhead?

  1. Repartition both DataFrames to one partition
    2. Broadcast the smaller DataFrame
    3. Collect the large DataFrame to the driver
    4. Sort both DataFrames globally before joining

Correct Answer: 2. Broadcast the smaller DataFrame

Explanation:

Broadcasting the smaller DataFrame can allow Spark to send a copy of that dataset to each executor so the large DataFrame does not need to be redistributed across the cluster for the join. This can substantially reduce shuffle traffic and improve performance when the smaller side is sufficiently small. Repartitioning everything to one partition removes parallelism and creates a bottleneck. Collecting a large DataFrame to the driver risks memory failure. A global sort also introduces additional work and is unnecessary for a broadcast join. Broadcast joins are especially useful for fact-to-dimension style workloads involving a large transactional table and a relatively small reference table.

Question 222.

Which Spark SQL function can explicitly mark a DataFrame as suitable for a broadcast join?

  1. repartition()
    2. cache()
    3. broadcast()
    4. coalesce()

Correct Answer: 3. broadcast()

Explanation:

broadcast() can be used to provide Spark with a broadcast hint for a DataFrame participating in a join. This tells the optimizer that the DataFrame is intended to be distributed to executors rather than shuffled like a larger dataset. The strategy is appropriate only when the broadcasted dataset is small enough to fit comfortably in executor memory. repartition() redistributes data into partitions, cache() stores computed data for reuse, and coalesce() typically reduces partition count. Using broadcast() with an overly large dataset can create memory pressure, so developers should use it only when the size characteristics justify the optimization.

Question 223.

A developer needs to retain all rows from the left DataFrame and only matching information from the right DataFrame. Which join type should be used?

  1. Left outer join
    2. Inner join
    3. Left anti join
    4. Cross join

Correct Answer: 1. Left outer join

Explanation:

A left outer join preserves every row from the left DataFrame. When a matching row exists on the right, the corresponding right-side values are included. When no match exists, Spark returns null values for the right-side columns. An inner join would discard unmatched left rows, a left anti join would return only unmatched left rows, and a cross join would create all possible combinations. Left outer joins are widely used in enrichment workloads where a primary dataset must be retained even when reference or lookup information is unavailable for some records.

Question 224.

Which join returns only rows from the left DataFrame for which no matching row exists in the right DataFrame?

  1. Left semi join
    2. Inner join
    3. Full outer join
    4. Left anti join

Correct Answer: 4. Left anti join

Explanation:

A left anti join returns only records from the left DataFrame that do not satisfy the join condition with any row on the right. It is useful for identifying missing records, new keys, unmatched transactions, or entities absent from a reference dataset. A left semi join performs the opposite existence test by returning matching left-side rows. An inner join returns matched records, while a full outer join preserves matched and unmatched rows from both sides. Left anti joins are particularly useful in reconciliation, change detection, and data-quality workflows where unmatched records need to be isolated.

Question 225.

Which join returns matching rows from the left DataFrame while excluding all columns from the right DataFrame?

  1. Full outer join
    2. Left semi join
    3. Left outer join
    4. Cross join

Correct Answer: 2. Left semi join

Explanation:

A left semi join performs an existence check against the right DataFrame and returns only rows from the left side that have at least one match. Importantly, the output includes only left-side columns. This makes it useful when the right DataFrame is needed solely to determine whether a corresponding key exists. A left outer join includes right-side columns, a full outer join retains unmatched rows from both datasets, and a cross join creates a Cartesian product. Semi joins can be efficient and expressive for membership-testing scenarios where no right-side attributes are needed in the final result.

Question 226.

Which Spark transformation is most likely to cause a shuffle because records with the same key must be brought together?

  1. select()
    2. withColumnRenamed()
    3. groupBy()
    4. lit()

Correct Answer: 3. groupBy()

Explanation:

groupBy() commonly causes a shuffle because rows containing the same grouping key may initially reside in many different partitions. Spark must redistribute records so that values belonging to the same key can be processed together during aggregation. select() usually projects columns without requiring redistribution, withColumnRenamed() changes metadata rather than data placement, and lit() adds constant expressions. Shuffles can involve network transfer, serialization, and disk activity, making them relatively expensive. Recognizing shuffle-producing operations is important when tuning Spark jobs, especially when grouping very large datasets or working with highly skewed keys.

Question 227.

Which DataFrame operation is generally a narrow transformation because each row can be processed independently within its existing partition?

  1. filter()
    2. distinct()
    3. repartition()
    4. groupBy()

Correct Answer: 1. filter()

Explanation:

filter() is generally a narrow transformation because Spark can evaluate the filter condition independently against records already present in each partition. The operation does not normally require records to move between executors. distinct(), repartition(), and groupBy() usually require broader data redistribution and therefore can produce shuffles. Narrow transformations are often less expensive because Spark can pipeline them with other operations inside the same stage. Filtering early in a query can also reduce the amount of data passed into later joins or aggregations, potentially improving overall workload efficiency.

Question 228.

A developer wants to inspect whether a DataFrame query includes Exchange operators and shuffle-related stages. Which method should be used?

  1. describe()
    2. printSchema()
    3. show()
    4. explain()

Correct Answer: 4. explain()

Explanation:

explain() displays Spark’s query plans and can expose physical operators such as scans, filters, joins, aggregations, exchanges, and sorts. An Exchange operator often indicates data redistribution and can help developers identify shuffle boundaries or expensive stages. describe() produces summary statistics, printSchema() displays column structure, and show() displays sample rows. Reviewing query plans is an important performance-tuning technique because it helps developers understand how Spark intends to execute their code rather than relying only on the appearance of the high-level DataFrame transformations.

Question 229.

Which optimization reduces I/O by reading only the columns required by a query from a columnar source such as Parquet?

  1. Column pruning
    2. Checkpointing
    3. Repartitioning
    4. Caching

Correct Answer: 1. Column pruning

Explanation:

Column pruning allows Spark to avoid reading columns that are not required by the query. This is especially effective with columnar storage formats such as Parquet, where individual columns can be read independently. For example, a query selecting only customer_id and revenue may avoid scanning dozens of unrelated fields. Checkpointing truncates lineage, repartitioning changes data distribution, and caching stores computed data for reuse. Column pruning reduces disk I/O and data processing, making it an important optimization for wide datasets containing many columns.

Question 230.

Which optimization attempts to apply filtering conditions at the data source so that fewer rows are read into Spark?

  1. Broadcast join
    2. Predicate pushdown
    3. Column aliasing
    4. Window partitioning

Correct Answer: 2. Predicate pushdown

Explanation:

Predicate pushdown allows Spark to pass supported filter conditions to a compatible data source so unnecessary rows can be eliminated before being fully read into the Spark execution engine. This can significantly reduce I/O and downstream processing. Broadcast joins optimize certain joins, column aliasing simply changes expression names, and window partitioning controls logical groups for analytical functions. Predicate pushdown works particularly well with formats and systems that can efficiently skip data based on stored statistics, indexes, or metadata. Applying selective filters early can therefore improve performance substantially.

Question 231.

Which storage format is particularly well suited to Spark analytics because it stores data in a columnar representation?

  1. Plain text
    2. Raw binary
    3. Parquet
    4. Unstructured log text

Correct Answer: 3. Parquet

Explanation:

Parquet is a columnar file format commonly used with Apache Spark for analytical workloads. Its column-oriented design allows Spark to read only the fields needed for a query and can support optimizations such as column pruning and predicate pushdown. Parquet also supports efficient compression and encoding because values of the same column and type are stored together. Plain text and raw binary formats generally lack the same rich schema and column-level optimization capabilities. Parquet is therefore a common choice for data lakes, intermediate analytical datasets, and reusable structured storage.

Question 232.

Which DataFrameWriter mode adds new records to an existing target without replacing the existing data?

  1. overwrite
    2. ignore
    3. errorIfExists
    4. append

Correct Answer: 4. append

Explanation:

append mode writes new records to an existing destination while preserving the data already stored there. It is commonly used for incremental ingestion where each run contributes additional records. overwrite replaces existing target data according to the data source’s semantics. ignore skips the write when the destination exists, while errorIfExists raises an error if existing data is detected. Developers should still consider duplicate handling, partitioning, and idempotency when using append because repeatedly executing the same job may add duplicate records unless the pipeline includes appropriate safeguards.

Question 233.

Which DataFrameWriter mode replaces existing data at the destination?

  1. overwrite
    2. append
    3. ignore
    4. errorIfExists

Correct Answer: 1. overwrite

Explanation:

overwrite mode replaces existing target data according to the behavior supported by the chosen data source and write configuration. It is useful when a dataset should be completely refreshed rather than incrementally extended. append adds new records, ignore skips writing if a target already exists, and errorIfExists fails instead of modifying existing content. Because overwrite can remove or replace previously stored information, it should be used carefully, especially with partitioned datasets or production storage locations where unintended deletion could have significant consequences.

Question 234.

A developer wants Spark to write output files into directory partitions based on the country column. Which DataFrameWriter method is most appropriate?

  1. repartition(“country”)
    2. partitionBy(“country”)
    3. groupBy(“country”)
    4. orderBy(“country”)

Correct Answer: 2. partitionBy(“country”)

Explanation:

partitionBy(“country”) instructs DataFrameWriter to organize output into directory partitions based on distinct values of the specified column. For example, records may be stored under paths such as country=US and country=DE. This can improve query efficiency when downstream workloads commonly filter by that partition column. repartition() changes runtime partition distribution but does not by itself define directory partitioning in the written dataset. groupBy() aggregates records, while orderBy() sorts them. Choosing suitable partition columns is important because excessively high cardinality can create many small directories and files.

Question 235.

Which operation should a developer consider when a DataFrame has thousands of very small partitions and the goal is to reduce them before writing output with minimal redistribution?

  1. collect()
    2. groupBy()
    3. coalesce()
    4. distinct()

Correct Answer: 3. coalesce()

Explanation:

coalesce() is commonly used to reduce the number of partitions while attempting to minimize shuffle overhead. It can combine existing partitions rather than fully redistributing all records. This makes it useful before writes when an excessive number of partitions would otherwise generate many small output files. collect() brings records to the driver and is unsuitable for this purpose, groupBy() performs aggregation, and distinct() removes duplicates. coalesce() can produce uneven partitions, so repartition() may still be preferable when balanced distribution matters more than avoiding a shuffle.

Question 236.

Which operation should a developer use when data must be redistributed more evenly across a new number of partitions, even if a shuffle is required?

  1. cache()
    2. limit()
    3. unpersist()
    4. repartition()

Correct Answer: 4. repartition()

Explanation:

repartition() performs data redistribution and can increase or decrease the number of partitions. Because it generally causes a shuffle, it is more expensive than coalesce() when simply reducing partitions, but it can create a more balanced distribution. This is useful when improving parallelism, preparing for downstream processing, or addressing uneven partition sizes. cache() stores data for reuse, limit() restricts row count, and unpersist() removes persisted data. repartition() can also partition data according to one or more expressions, which may benefit later joins or writes depending on the workload.

Question 237.

A DataFrame will be reused by several actions after an expensive sequence of transformations. Which technique can avoid repeatedly recomputing the same lineage?

  1. cache()
    2. dropDuplicates()
    3. orderBy()
    4. alias()

Correct Answer: 1. cache()

Explanation:

cache() marks a DataFrame for persistence so computed partitions can be reused across subsequent actions rather than recalculating the entire transformation lineage each time. This can be valuable when an expensive intermediate dataset feeds multiple reports, counts, joins, or analytical operations. dropDuplicates() removes repeated rows, orderBy() sorts data, and alias() changes how an expression or DataFrame is referenced. Caching is not automatically beneficial for every workload because it consumes storage resources. It is most useful when the data is reused enough that avoiding recomputation outweighs the cost of materializing and retaining it.

Question 238.

Which DataFrame method should be used when the developer wants explicit control over the storage level used for reusable intermediate data?

  1. show()
    2. persist()
    3. collect()
    4. checkpoint()

Correct Answer: 2. persist()

Explanation:

persist() allows developers to retain a DataFrame using an explicitly selected storage level, providing more control than the default behavior associated with cache(). Depending on available storage levels and runtime configuration, persisted data may be stored in memory, on disk, or using a combination of mechanisms. show() displays records, collect() returns them to the driver, and checkpoint() materializes data while truncating lineage. persist() is useful when a workload needs reusable intermediate results but the developer wants to balance speed, memory consumption, and disk usage deliberately.

Question 239.

Which method should be called when a previously cached DataFrame is no longer needed and its storage resources should be released?

  1. drop()
    2. clear()
    3. unpersist()
    4. release()

Correct Answer: 3. unpersist()

Explanation:

unpersist() removes cached or persisted blocks associated with a DataFrame so memory or disk resources can be reclaimed. This is especially useful in long-running Spark applications that cache several large intermediate datasets over time. Leaving unnecessary DataFrames persisted can reduce the resources available for later computations and potentially cause eviction or performance degradation. drop() removes DataFrame columns, while clear() and release() are not the standard DataFrame methods for removing persisted blocks. Explicitly unpersisting data after its final reuse can improve resource management.

Question 240.

A Spark application has built a very long lineage through many transformations, and the developer wants to materialize the DataFrame while truncating that lineage. Which method is most appropriate?

  1. cache()
    2. explain()
    3. repartition()
    4. checkpoint()

Correct Answer: 4. checkpoint()

Explanation:

checkpoint() materializes a DataFrame to configured checkpoint storage and cuts off the previous lineage, creating a new starting point for subsequent computation. This can be beneficial when iterative or complex pipelines produce extremely long dependency chains that increase planning complexity or make recovery more expensive. cache() may retain computed data but does not provide the same lineage-truncation semantics. explain() only displays query plans, and repartition() redistributes data. Checkpointing introduces additional storage and execution cost, so it should be used selectively where the benefits of shortening lineage justify that overhead.