View Full CWNP CWNA-109 Exam Dumps and Practice Test Dumps
Question 141.
Which 802.11 amendment introduced High Throughput operation and MIMO as major WLAN capabilities?
- 802.11a
2. 802.11n
3. 802.11b
4. 802.11d
Correct Answer: 2. 802.11n
Explanation:
IEEE 802.11n introduced High Throughput WLAN operation and made MIMO a major component of modern Wi-Fi. It also introduced features such as wider 40 MHz channels, frame aggregation, and other efficiency improvements. 802.11a and 802.11b are earlier PHY technologies, while 802.11d relates to regulatory-domain information. 802.11n can operate in both 2.4 GHz and 5 GHz, subject to regulatory and device support. Its introduction represented a major increase in potential throughput compared with earlier Wi-Fi generations, although actual application throughput remains lower than advertised PHY rates because of contention, management traffic, acknowledgments, interframe spaces, and other protocol overhead.
Question 142.
Which 802.11 amendment introduced Very High Throughput operation primarily in the 5 GHz band?
- 802.11ac
2. 802.11g
3. 802.11d
4. 802.11h
Correct Answer: 1. 802.11ac
Explanation:
IEEE 802.11ac introduced Very High Throughput operation and was designed primarily for the 5 GHz band. It expanded capabilities such as wider channel widths, higher-order modulation, increased spatial streams, and multi-user MIMO in later implementations. 802.11g is an older 2.4 GHz PHY, 802.11d addresses regulatory-domain information, and 802.11h introduced spectrum-management capabilities such as DFS-related functions. Although 802.11ac can provide high peak PHY rates, WLAN designers must still consider channel reuse, client capabilities, airtime efficiency, and channel width because the widest possible channel is not always the best choice in dense enterprise deployments.
Question 143.
Which 802.11 generation introduced High Efficiency WLAN operation and technologies such as OFDMA and BSS Coloring?
- 802.11b
2. 802.11n
3. 802.11ax
4. 802.11a
Correct Answer: 3. 802.11ax
Explanation:
IEEE 802.11ax introduced High Efficiency WLAN operation and is associated commercially with Wi-Fi 6. Major features include OFDMA, BSS Coloring, improved MU-MIMO capabilities, Target Wake Time, and other enhancements designed to improve efficiency in dense environments. 802.11n introduced High Throughput and MIMO, while 802.11a and 802.11b are much older PHY technologies. The goal of 802.11ax is not simply to maximize one client’s peak data rate; it also improves aggregate efficiency when many devices share the same RF environment. This makes it particularly relevant to enterprise, education, stadium, and high-density deployments.
Question 144.
Which commercial Wi-Fi generation name corresponds to IEEE 802.11ax?
- Wi-Fi 4
2. Wi-Fi 5
3. Wi-Fi 7
4. Wi-Fi 6
Correct Answer: 4. Wi-Fi 6
Explanation:
IEEE 802.11ax is commercially known as Wi-Fi 6. Wi-Fi 4 generally corresponds to 802.11n, while Wi-Fi 5 corresponds to 802.11ac. Wi-Fi 6E refers to Wi-Fi 6 operation extended into the 6 GHz band. Generational naming was introduced to make Wi-Fi technology easier for users and vendors to understand than amendment numbers alone. For certification preparation, it is useful to know both naming systems because technical documentation may use the IEEE amendment while product marketing uses the Wi-Fi generation name. The capabilities of a device also depend on its specific implementation rather than the generation label alone.
Question 145.
Which term describes the maximum raw transmission rate negotiated at the physical layer rather than the actual user application throughput?
- PHY data rate
2. TCP goodput
3. Application response time
4. Internet bandwidth
Correct Answer: 1. PHY data rate
Explanation:
The PHY data rate is the raw transmission rate used by the wireless physical layer. It is not the same as actual application throughput because Wi-Fi includes substantial overhead from management frames, control frames, acknowledgments, contention, interframe spaces, encryption, retransmissions, aggregation behavior, and higher-layer protocols. TCP and application goodput are therefore usually significantly lower than the advertised PHY rate. This distinction is important when setting realistic expectations. A client showing a high PHY rate does not necessarily have that same amount of usable throughput available, especially when many stations share the channel or interference and retries are present.
Question 146.
Which factor most directly limits the maximum number of spatial streams a client can use with an access point?
- The AP’s Ethernet cable color
2. The lower supported spatial-stream capability of the two devices
3. The SSID name length
4. The DHCP lease time
Correct Answer: 2. The lower supported spatial-stream capability of the two devices
Explanation:
A wireless link can use only as many spatial streams as both endpoints support. For example, if an access point supports four spatial streams but the client supports only two, the link cannot use more than two client spatial streams. Other RF conditions may reduce the practical rate further. Ethernet cable color, SSID length, and DHCP lease duration have no relationship to spatial-stream capability. This is one reason WLAN designers should evaluate actual client devices rather than relying solely on the maximum specifications of enterprise access points. Most mobile clients support fewer spatial streams than high-end infrastructure radios.
Question 147.
Which Wi-Fi feature allows an access point to transmit independent spatial streams to more than one compatible client during the same transmission opportunity?
- DFS
2. WMM
3. MU-MIMO
4. TKIP
Correct Answer: 3. MU-MIMO
Explanation:
Multi-User MIMO allows an access point to use multiple spatial streams to communicate with multiple compatible clients during the same transmission opportunity. This can improve aggregate efficiency when client geometry, capabilities, and traffic patterns are suitable. DFS protects radar systems, WMM provides quality-of-service prioritization, and TKIP is an obsolete encryption mechanism. MU-MIMO differs from single-user MIMO, where multiple spatial streams are directed to one client. Its effectiveness depends on access point implementation, client support, signal quality, and spatial separation, so the presence of MU-MIMO support does not guarantee dramatic performance gains in every environment.
Question 148.
Which statement best describes transmit beamforming?
- It changes the DHCP server used by a client
2. It increases the number of SSIDs
3. It forces clients to use 2.4 GHz
4. It adjusts transmission characteristics to improve signal delivery toward a client**
Correct Answer: 4. It adjusts transmission characteristics to improve signal delivery toward a client
Explanation:
Transmit beamforming uses multiple transmit chains and signal-processing techniques to adjust phase and amplitude so the resulting RF energy combines more favorably at the intended receiver. This can improve signal quality and reliability for compatible clients. It does not change DHCP configuration, SSID count, or frequency-band selection by itself. Beamforming should not be imagined as a perfectly narrow physical beam; rather, it manipulates the radio wavefront to create constructive effects in useful directions. Its real-world benefit varies with client capabilities, multipath conditions, channel knowledge, and the implementation used by the WLAN infrastructure.
Question 149.
Which PHY characteristic usually increases when channel width changes from 20 MHz to 40 MHz, assuming other conditions remain similar?
- Potential PHY data rate
2. Number of independent channels available for reuse
3. Amount of free spectrum
4. Client battery life automatically doubles
Correct Answer: 1. Potential PHY data rate
Explanation:
A wider channel provides more spectrum for a single transmission and can therefore support a higher potential PHY data rate, assuming similar modulation, coding, and spatial-stream conditions. The tradeoff is that wider channels consume more spectrum and reduce the number of independent channels available for reuse. This can be harmful in dense WLAN deployments where aggregate capacity depends heavily on channel reuse. Wider channels do not create additional spectrum or automatically improve battery life. WLAN design should therefore balance the desire for higher per-client peak rates against the need for efficient spectrum reuse across many access points.
Question 150.
Which channel width is generally the most spectrum-efficient starting point for very dense enterprise deployments where channel reuse is a priority?
- 160 MHz everywhere
2. 20 MHz
3. 80 MHz everywhere
4. The widest width supported by every AP
Correct Answer: 2. 20 MHz
Explanation:
Twenty-megahertz channels are often the most spectrum-efficient starting point in dense enterprise environments because they maximize the number of independent channels available for reuse. Wider channels can increase individual PHY rates but consume more spectrum and force more neighboring APs to share the same channels. This may increase contention and reduce aggregate capacity. The correct design still depends on application requirements, regulatory spectrum, client density, and supported bands, but wide channels should not be assumed to be better simply because they advertise higher rates. Dense WLANs are usually optimized for aggregate airtime efficiency rather than single-client speed.
Question 151.
Which term describes the process by which a client evaluates available BSSs and chooses a candidate access point when moving through an ESS?
- Fragmentation
2. Aggregation
3. Roaming
4. Encryption
Correct Answer: 3. Roaming
Explanation:
Roaming is the process in which a client moves from one access point or BSS to another within an Extended Service Set while attempting to maintain network connectivity. The client generally decides when and where to roam based on its own algorithms, signal conditions, scan results, and available infrastructure assistance. Fragmentation divides frames, aggregation combines frames, and encryption protects confidentiality. Successful roaming depends on adequate cell overlap, suitable candidate APs, authentication performance, client behavior, and application tolerance. Real-time applications such as voice are particularly sensitive to roaming delays and packet loss.
Question 152.
Which 802.11 amendment can help clients discover neighboring access points more efficiently through radio resource measurements?
- 802.11i
2. 802.11e
3. 802.11w
4. 802.11k**
Correct Answer: 4. 802.11k
Explanation:
IEEE 802.11k provides radio resource measurement capabilities that can help clients obtain information about the wireless environment, including neighboring BSSs. Neighbor information can reduce the amount of time a client spends scanning blindly across channels during roaming. 802.11i focuses on security, 802.11e introduced QoS improvements, and 802.11w added protection for selected management frames. 802.11k is often discussed together with 802.11r and 802.11v because the three amendments can assist roaming in different ways. Client support and implementation quality remain important because these features do not force all clients to behave identically.
Question 153.
Which 802.11 amendment introduced Fast BSS Transition?
- 802.11r
2. 802.11k
3. 802.11v
4. 802.11h
Correct Answer: 1. 802.11r
Explanation:
IEEE 802.11r introduced Fast BSS Transition, which reduces the authentication-related delay associated with moving between access points in the same mobility environment. This is particularly valuable for real-time applications such as voice, where long roaming interruptions can cause audible gaps or dropped calls. 802.11k helps with radio resource measurements and neighbor information, while 802.11v includes network-management enhancements such as BSS Transition Management. 802.11h includes spectrum-management mechanisms. Fast roaming should be tested with the actual client population because compatibility and implementation behavior can vary among devices and operating systems.
Question 154.
Which 802.11 amendment includes BSS Transition Management, allowing infrastructure to suggest alternative BSSs to a client?
- 802.11a
2. 802.11v
3. 802.11b
4. 802.11d
Correct Answer: 2. 802.11v
Explanation:
IEEE 802.11v includes network-management enhancements such as BSS Transition Management. This capability allows infrastructure to provide a client with information or recommendations about alternative BSSs. The client still ultimately decides whether to move. 802.11a and 802.11b define older PHY technologies, while 802.11d relates to regulatory-domain information. In well-designed enterprise WLANs, 802.11v may work alongside 802.11k and 802.11r to improve roaming efficiency. However, infrastructure support alone is not enough; client compatibility and roaming algorithms still determine real-world behavior.
Question 155.
Which factor is most likely to cause a sticky client to remain associated with a distant AP instead of roaming to a closer one?
- Client roaming algorithm and thresholds
2. Ethernet cable category only
3. DNS TTL
4. Switch port description
Correct Answer: 1. Client roaming algorithm and thresholds
Explanation:
The client generally controls roaming decisions, so its driver, operating system, signal thresholds, and roaming algorithm strongly influence whether it leaves a distant AP. A sticky client may remain associated even when another AP offers a better signal because its roaming threshold has not yet been reached. Ethernet cabling, DNS TTL, and switch-port descriptions do not determine WLAN roaming behavior. WLAN designers can improve conditions through suitable cell overlap, transmit power, channel plans, and supported roaming-assistance features, but they cannot assume all clients will roam at the same RSSI or according to identical logic.
Question 156.
Which design practice most directly helps support reliable voice roaming?
- Configure every AP to maximum transmit power
2. Use as many SSIDs as possible
3. Provide appropriate cell overlap and validate with representative voice clients
4. Use only 2.4 GHz regardless of environment
Correct Answer: 3. Provide appropriate cell overlap and validate with representative voice clients
Explanation:
Reliable voice roaming requires enough overlap between neighboring coverage cells so the client can discover and move to a suitable candidate before the current connection becomes unusable. The exact target depends on client requirements and design criteria. Validation should use representative voice devices because roaming behavior differs among vendors and operating systems. Maximum AP power can produce oversized cells and sticky-client behavior, while excessive SSIDs add overhead. Restricting operation to one band regardless of environmental needs is also poor design. Voice WLAN validation should include roaming delay, packet loss, signal quality, channel utilization, and application behavior.
Question 157.
Which term describes the amount of useful application data successfully delivered, excluding protocol overhead and retransmissions?
- Goodput
2. PHY rate
3. EIRP
4. RSSI
Correct Answer: 1. Goodput
Explanation:
Goodput refers to the useful application-level data successfully delivered over a network, excluding protocol overhead, retransmissions, headers, and other non-payload traffic. It is therefore lower than the PHY data rate and often lower than raw transport-layer throughput. EIRP describes transmitted RF power, while RSSI represents received signal strength. Goodput is a more realistic metric for what users actually experience when transferring files or using applications. WLAN testing should not equate advertised link speed with user throughput because contention, acknowledgments, encryption, aggregation, retries, and higher-layer protocols all consume capacity.
Question 158.
Which factor can cause application throughput to be much lower than the negotiated PHY data rate even in a healthy WLAN?
- The PHY rate always equals TCP throughput
2. 802.11 contention and protocol overhead consume airtime
3. APs cannot transmit data frames
4. Encryption always reduces throughput to zero
Correct Answer: 2. 802.11 contention and protocol overhead consume airtime
Explanation:
The negotiated PHY data rate represents raw radio transmission speed, not the amount of application payload delivered each second. Wi-Fi must account for interframe spaces, random backoff, acknowledgments, management traffic, headers, security overhead, aggregation behavior, retransmissions, and shared-medium contention. Higher-layer protocols also introduce additional overhead. Therefore, actual TCP throughput or application goodput is normally well below the PHY rate even when the WLAN is functioning correctly. The difference becomes larger when channel utilization is high, retries increase, or many clients share the same airtime.
Question 159.
Which post-deployment test is most useful for confirming that a high-density WLAN actually meets expected user-capacity requirements?
- Capacity and load validation using representative clients and traffic
2. Reviewing only the floor plan
3. Checking only AP serial numbers
4. Measuring only one RSSI point near each AP
Correct Answer: 1. Capacity and load validation using representative clients and traffic
Explanation:
Coverage measurements alone cannot prove that a high-density WLAN has sufficient capacity. Capacity validation should use representative client devices and realistic traffic loads to determine whether airtime, channel reuse, application performance, latency, and throughput remain acceptable under expected demand. Floor plans and inventory checks provide useful documentation but do not measure real performance. A single RSSI point near each AP confirms very little about congestion or aggregate capacity. High-density designs should be validated under conditions that approximate actual usage because client count and traffic patterns can dramatically change medium contention.
Question 160.
A client shows a high PHY rate but users still report slow file transfers. Which troubleshooting approach is most appropriate?
- Assume the PHY rate proves the WLAN is healthy
2. Immediately replace all access points
3. Disable encryption and leave it disabled
4. Examine retries, airtime utilization, contention, channel width, interference, TCP behavior, and wired-path performance**
Correct Answer: 4. Examine retries, airtime utilization, contention, channel width, interference, TCP behavior, and wired-path performance
Explanation:
A high PHY rate only indicates the current radio transmission rate and does not prove that application performance is good. Slow file transfers can result from retries, contention, excessive channel utilization, interference, insufficient channel reuse, TCP limitations, wired bottlenecks, server performance, or application behavior. Troubleshooting should therefore examine the complete path rather than focus on one wireless metric. Disabling security is not an appropriate permanent fix, and replacing all APs without evidence is wasteful. A structured process should correlate RF measurements, protocol behavior, transport-layer performance, and wired-network data before deciding which component is responsible.