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Certified Data Engineer Associate Practice Test 21

Question 200

Two DataFrames have identical logical columns but their physical column orders differ after separate ingestion changes.

Which acceptance result most directly demonstrates that the intended solution works?

  1. The output has one instance of every identical row after explicit deduplication.
  2. Rows from both sources retain the correct values under each named column.
  3. Each fact row matches only the dimension record with its key and effective date.
  4. A day with five events from two devices yields a distinct-device count of two.

Explanation

Correct Answer

B:

Name-based union reduces accidental column swaps when schemas have different field order.

Incorrect Answers

A:

The output has one instance of every identical row after explicit deduplication. That finding does not establish that rows from both sources retain the correct values under each named column.

C:

Each fact row matches only the dimension record with its key and effective date. That finding does not establish that rows from both sources retain the correct values under each named column.

D:

A day with five events from two devices yields a distinct-device count of two. That finding does not establish that rows from both sources retain the correct values under each named column.

Question 201

A PySpark developer expects DataFrame.union to remove duplicate rows just like a SQL UNION statement.

Which implementation decision best addresses this requirement?

  1. Use union followed by distinct if duplicate elimination is required for DataFrame rows.
  2. Use crossJoin only when the intended result is a Cartesian product.
  3. Use explicit null-safe equality only if the business rule actually treats nulls as matching.
  4. Use approx_count_distinct on the user key with an appropriate accuracy parameter.

Explanation

Correct Answer

A:

PySpark DataFrame union appends rows without guaranteeing deduplication; distinct is a separate operation. The selected implementation is the one directly aligned with the constraints in the scenario.

Incorrect Answers

B:

A cross join constructs every pair of rows and can grow explosively for large inputs.

C:

SQL and DataFrame ordinary equality do not match null to null; null-safe comparison has different semantics.

D:

Approximate distinct aggregates can reduce resource costs when exact cardinality is not required.

Question 202

A PySpark developer expects DataFrame.union to remove duplicate rows just like a SQL UNION statement.

Which acceptance result most directly demonstrates that the intended solution works?

  1. The controlled input produces exactly thirty segment-tier pairs.
  2. The test demonstrates the chosen null policy, including how two null keys are treated.
  3. The output has one instance of every identical row after explicit deduplication.
  4. The result is close to a sampled exact distinct count within the accepted accuracy tolerance.

Explanation

Correct Answer

C:

PySpark DataFrame union appends rows without guaranteeing deduplication; distinct is a separate operation.

Incorrect Answers

A:

The controlled input produces exactly thirty segment-tier pairs. That finding does not establish that the output has one instance of every identical row after explicit deduplication.

B:

The test demonstrates the chosen null policy, including how two null keys are treated. That finding does not establish that the output has one instance of every identical row after explicit deduplication.

D:

The result is close to a sampled exact distinct count within the accepted accuracy tolerance. That finding does not establish that the output has one instance of every identical row after explicit deduplication.

Question 203

A report needs all combinations of ten marketing segments and three geographic tiers without any join keys.

Which implementation decision best addresses this requirement?

  1. Use crossJoin only when the intended result is a Cartesian product.
  2. Join on both business-key columns using a conjunctive join predicate.
  3. Group by store and date, then aggregate sum(amount) for total revenue.
  4. Use avg or mean over the shipment duration column grouped by route.

Explanation

Correct Answer

A:

A cross join constructs every pair of rows and can grow explosively for large inputs. The selected implementation is the one directly aligned with the constraints in the scenario.

Incorrect Answers

B:

A multi-key join constrains rows to the same account and date rather than multiplying cross-date matches.

C:

Grouping creates one aggregate per grouping key and sum computes the requested financial measure.

D:

An arithmetic mean answers the per-shipment average question; sum answers a different aggregate.

Question 204

A report needs all combinations of ten marketing segments and three geographic tiers without any join keys.

Which acceptance result most directly demonstrates that the intended solution works?

  1. Each fact row matches only the dimension record with its key and effective date.
  2. Two rows for the same store and day contribute one summed revenue record.
  3. For durations of 10 and 20 minutes the reported route average is 15 minutes.
  4. The controlled input produces exactly thirty segment-tier pairs.

Explanation

Correct Answer

D:

A cross join constructs every pair of rows and can grow explosively for large inputs.

Incorrect Answers

A:

Each fact row matches only the dimension record with its key and effective date. That finding does not establish that the controlled input produces exactly thirty segment-tier pairs.

B:

Two rows for the same store and day contribute one summed revenue record. That finding does not establish that the controlled input produces exactly thirty segment-tier pairs.

C:

For durations of 10 and 20 minutes the reported route average is 15 minutes. That finding does not establish that the controlled input produces exactly thirty segment-tier pairs.

Question 205

A fact and dimension use both account_id and effective_date as keys, and joining only account_id produces duplicate matches.

Which implementation decision best addresses this requirement?

  1. Use explicit null-safe equality only if the business rule actually treats nulls as matching.
  2. Join on both business-key columns using a conjunctive join predicate.
  3. Aggregate countDistinct(device_id) grouped by event date.
  4. Apply row_number over a customer-key window ordered by descending timestamp and keep rank one.

Explanation

Correct Answer

B:

A multi-key join constrains rows to the same account and date rather than multiplying cross-date matches. The selected implementation is the one directly aligned with the constraints in the scenario.

Incorrect Answers

A:

SQL and DataFrame ordinary equality do not match null to null; null-safe comparison has different semantics.

C:

Counting distinct identifiers avoids treating repeated events from one device as separate devices.

D:

A deterministic latest-record window supports deduplication by business key with explicit ordering.

Question 206

A fact and dimension use both account_id and effective_date as keys, and joining only account_id produces duplicate matches.

Which acceptance result most directly demonstrates that the intended solution works?

  1. The test demonstrates the chosen null policy, including how two null keys are treated.
  2. A day with five events from two devices yields a distinct-device count of two.
  3. The retained customer row has the newest timestamp for each key and ties follow the documented tie-break rule.
  4. Each fact row matches only the dimension record with its key and effective date.

Explanation

Correct Answer

D:

A multi-key join constrains rows to the same account and date rather than multiplying cross-date matches.

Incorrect Answers

A:

The test demonstrates the chosen null policy, including how two null keys are treated. That finding does not establish that each fact row matches only the dimension record with its key and effective date.

B:

A day with five events from two devices yields a distinct-device count of two. That finding does not establish that each fact row matches only the dimension record with its key and effective date.

C:

The retained customer row has the newest timestamp for each key and ties follow the documented tie-break rule. That finding does not establish that each fact row matches only the dimension record with its key and effective date.

Question 207

A developer joins facts where some business keys are null and expects ordinary equals comparison to match two null keys.

Which implementation decision best addresses this requirement?

  1. Group by store and date, then aggregate sum(amount) for total revenue.
  2. Use approx_count_distinct on the user key with an appropriate accuracy parameter.
  3. Use explicit null-safe equality only if the business rule actually treats nulls as matching.
  4. Apply dropDuplicates over the full columns or the exact duplicate-identification subset.

Explanation

Correct Answer

C:

SQL and DataFrame ordinary equality do not match null to null; null-safe comparison has different semantics. The selected implementation is the one directly aligned with the constraints in the scenario.

Incorrect Answers

A:

Grouping creates one aggregate per grouping key and sum computes the requested financial measure.

B:

Approximate distinct aggregates can reduce resource costs when exact cardinality is not required.

D:

DataFrame deduplication removes repeated records according to the chosen identity columns.

Question 208

A developer joins facts where some business keys are null and expects ordinary equals comparison to match two null keys.

Which acceptance result most directly demonstrates that the intended solution works?

  1. The test demonstrates the chosen null policy, including how two null keys are treated.
  2. Two rows for the same store and day contribute one summed revenue record.
  3. The result is close to a sampled exact distinct count within the accepted accuracy tolerance.
  4. Exact repeated input rows appear once after the transformation.

Explanation

Correct Answer

A:

SQL and DataFrame ordinary equality do not match null to null; null-safe comparison has different semantics.

Incorrect Answers

B:

Two rows for the same store and day contribute one summed revenue record. That finding does not establish that the test demonstrates the chosen null policy, including how two null keys are treated.

C:

The result is close to a sampled exact distinct count within the accepted accuracy tolerance. That finding does not establish that the test demonstrates the chosen null policy, including how two null keys are treated.

D:

Exact repeated input rows appear once after the transformation. That finding does not establish that the test demonstrates the chosen null policy, including how two null keys are treated.

Question 209

A sales dashboard requires gross revenue grouped by store and business day from an orders DataFrame.

Which implementation decision best addresses this requirement?

  1. Aggregate countDistinct(device_id) grouped by event date.
  2. Use avg or mean over the shipment duration column grouped by route.
  3. Group by store and date, then aggregate sum(amount) for total revenue.
  4. Deduplicate on the intended event or order-line identity, not on a broader customer identifier.

Explanation

Correct Answer

C:

Grouping creates one aggregate per grouping key and sum computes the requested financial measure. The selected implementation is the one directly aligned with the constraints in the scenario.

Incorrect Answers

A:

Counting distinct identifiers avoids treating repeated events from one device as separate devices.

B:

An arithmetic mean answers the per-shipment average question; sum answers a different aggregate.

D:

The key choice determines the unit of uniqueness and must reflect the data grain.

Question 210

A sales dashboard requires gross revenue grouped by store and business day from an orders DataFrame.

Which acceptance result most directly demonstrates that the intended solution works?

  1. A day with five events from two devices yields a distinct-device count of two.
  2. Two rows for the same store and day contribute one summed revenue record.
  3. For durations of 10 and 20 minutes the reported route average is 15 minutes.
  4. Two legitimate orders for the same customer remain while true duplicate order lines collapse.

Explanation

Correct Answer

B:

Grouping creates one aggregate per grouping key and sum computes the requested financial measure.

Incorrect Answers

A:

A day with five events from two devices yields a distinct-device count of two. That finding does not establish that two rows for the same store and day contribute one summed revenue record.

C:

For durations of 10 and 20 minutes the reported route average is 15 minutes. That finding does not establish that two rows for the same store and day contribute one summed revenue record.

D:

Two legitimate orders for the same customer remain while true duplicate order lines collapse. That finding does not establish that two rows for the same store and day contribute one summed revenue record.

Certified Data Engineer Associate Practice Tests

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