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Cisco Certified Network Associate (CCNA) 200-301 Practice Test 7

Question 60

At a satellite office, the security and networking lead must transfer a critical configuration file reliably and recover missing segments in order. During review, someone proposes: "Use UDP alone and assume all payloads arrive." Which technical explanation most directly shows why this proposal does not solve the requirement?

  1. UDP does not provide transport-level reliable delivery.
  2. IP forwarding does not track ordered application bytes.
  3. ICMP echo is a diagnostic packet exchange, not a standard reliable file session.
  4. TCP offers ordered delivery and retransmission when segments are lost.

Explanation

Correct Answer

A:

UDP does not provide transport-level reliable delivery. The effective remedy is to use a TCP-based transfer with acknowledgment and retransmission.

Incorrect Answers

B:

IP forwarding does not track ordered application bytes. It concerns a different proposed change, not the change being evaluated.

C:

ICMP echo is a diagnostic packet exchange, not a standard reliable file session. This observation would apply to another device or feature, not the proposed use udp alone and assume all payloads arrive. For this scenario, uDP does not provide transport-level reliable delivery is the direct cause.

D:

TCP offers ordered delivery and retransmission when segments are lost. A true general network fact is not necessarily the direct diagnosis. The named change was use udp alone and assume all payloads arrive, whose relevant defect is that uDP does not provide transport-level reliable delivery.

Question 61

At a nonprofit organization, a network operations engineer needs voice samples delivered promptly and accepts application-level concealment of occasional loss. During review, someone proposes: "Force TCP retransmission of every late audio frame." Which technical explanation most directly shows why this proposal does not solve the requirement?

  1. A resolver transport is not an audio packetization mechanism.
  2. Late audio arriving after playback time reduces usefulness.
  3. ARP maps neighbor IP-to-MAC rather than transporting audio streams.
  4. Real-time media often favors timely datagrams over TCP head-of-line retransmission delays.

Explanation

Correct Answer

B:

Late audio arriving after playback time reduces usefulness. The effective remedy is to use a UDP-based real-time stream with application jitter management.

Incorrect Answers

A:

A resolver transport is not an audio packetization mechanism. It concerns a different proposed change, not the change being evaluated.

C:

ARP maps neighbor IP-to-MAC rather than transporting audio streams. A true general network fact is not necessarily the direct diagnosis. The named change was force tcp retransmission of every late audio frame, whose relevant defect is that late audio arriving after playback time reduces usefulness.

D:

Real-time media often favors timely datagrams over TCP head-of-line retransmission delays. That distinction is technically relevant elsewhere, but it does not identify the failure of the proposed force tcp retransmission of every late audio frame. The actual issue is that late audio arriving after playback time reduces usefulness.

Question 62

At a supply depot, the infrastructure lead is diagnosing a TCP connection where a server never acknowledges the client SYN after a firewall change. During review, someone proposes: "Check the UDP checksum as proof a TCP handshake succeeded." Which technical explanation most directly shows why this proposal does not solve the requirement?

  1. Bridge priority does not acknowledge TCP sessions.
  2. SYN, SYN-ACK and ACK establish TCP connection state before payload exchange.
  3. Transport ports and 802.1Q tags are different header fields.
  4. UDP is connectionless and has no SYN/ACK handshake.

Explanation

Correct Answer

D:

UDP is connectionless and has no SYN/ACK handshake. The effective remedy is to inspect stateful filtering and the three-way handshake path.

Incorrect Answers

A:

Bridge priority does not acknowledge TCP sessions. It concerns a different proposed change, not the change being evaluated.

B:

SYN, SYN-ACK and ACK establish TCP connection state before payload exchange. A true general network fact is not necessarily the direct diagnosis. The named change was check the udp checksum as proof a tcp handshake succeeded, whose relevant defect is that uDP is connectionless and has no SYN/ACK handshake.

C:

Transport ports and 802.1Q tags are different header fields. That distinction is technically relevant elsewhere, but it does not identify the failure of the proposed check the udp checksum as proof a tcp handshake succeeded. The actual issue is that uDP is connectionless and has no SYN/ACK handshake.

Question 63

At a warehouse, the branch support lead must explain why UDP name queries can be retried by a resolver even though the transport is connectionless. During review, someone proposes: "Require each DNS/UDP packet to receive a TCP ACK." Which technical explanation most directly shows why this proposal does not solve the requirement?

  1. UDP lacks built-in acknowledgments; DNS clients can retry at the application layer.
  2. Ethernet bridge learning cannot implement application retries.
  3. UDP does not guarantee ordering or recovery.
  4. TCP ACK numbers are not generated for UDP datagrams.

Explanation

Correct Answer

D:

TCP ACK numbers are not generated for UDP datagrams. The effective remedy is to let the DNS application use its own timeout and retry handling above UDP.

Incorrect Answers

A:

UDP lacks built-in acknowledgments; DNS clients can retry at the application layer. A true general network fact is not necessarily the direct diagnosis. The named change was require each dns/udp packet to receive a tcp ack, whose relevant defect is that tCP ACK numbers are not generated for UDP datagrams.

B:

Ethernet bridge learning cannot implement application retries. It concerns a different proposed change, not the change being evaluated.

C:

UDP does not guarantee ordering or recovery. The statement addresses a different mechanism. Here the engineer specifically proposed require each dns/udp packet to receive a tcp ack; the decisive limitation is that tCP ACK numbers are not generated for UDP datagrams.

Question 64

At a university, the branch support lead needs to select a protocol behavior when the application must detect receiver flow-control capacity during a long transfer. During review, someone proposes: "Use only an IP subnet mask as a receive window." Which technical explanation most directly shows why this proposal does not solve the requirement?

  1. TCP receivers advertise windows so senders can avoid overwhelming receive buffers.
  2. UDP multicast does not offer receiver-advertised TCP windows.
  3. LLDP advertises link neighbors, not stream byte positions.
  4. A subnet mask defines addressing boundaries, not transport buffering.

Explanation

Correct Answer

D:

A subnet mask defines addressing boundaries, not transport buffering. The effective remedy is to use TCP window-based flow control on the established session.

Incorrect Answers

A:

TCP receivers advertise windows so senders can avoid overwhelming receive buffers. That distinction is technically relevant elsewhere, but it does not identify the failure of the proposed use only an ip subnet mask as a receive window. The actual issue is that a subnet mask defines addressing boundaries, not transport buffering.

B:

UDP multicast does not offer receiver-advertised TCP windows. The statement addresses a different mechanism. Here the engineer specifically proposed use only an ip subnet mask as a receive window; the decisive limitation is that a subnet mask defines addressing boundaries, not transport buffering.

C:

LLDP advertises link neighbors, not stream byte positions. It concerns a different proposed change, not the change being evaluated.

Question 65

At a stadium, the branch support lead must document the network address containing host 10.167.202.126/24. Which address is that network ID?

  1. 10.167.202.0
  2. 10.167.201.0
  3. 10.167.202.255
  4. 10.167.203.0

Explanation

Correct Answer

A:

Masking 10.167.202.126 with /24 yields network 10.167.202.0; the subnet block contains 256 addresses through 10.167.202.255. That is the correct network ID for an SVI or static route.

Incorrect Answers

B:

This address identifies the adjacent lower block, not the /24 network containing 10.167.202.126. A network ID is obtained by zeroing all 8 host bits.

C:

10.167.202.255 is the last address in the block, not its network address. A broadcast address has host bits set to one.

D:

This is the next subnet after 10.167.202.0/24; the given host 10.167.202.126 resides in the preceding block. The prefix boundary is fixed by 255.255.255.0.

Question 66

At a field-service firm, the on-call technician reviews host 10.63.114.33/22. Which IPv4 address is the directed broadcast of that subnet?

  1. 10.63.115.254
  2. 10.63.115.255
  3. 10.63.116.0
  4. 10.63.112.0

Explanation

Correct Answer

B:

For 10.63.112.0/22, all 10 host bits set to one yield broadcast 10.63.115.255. The final usable host, if any, is one address before it.

Incorrect Answers

A:

10.63.115.254 is the highest usable host in the /22 block, not the directed broadcast. It lacks the all-ones host pattern.

C:

10.63.116.0 begins the next subnet block. It cannot be the broadcast for the subnet containing 10.63.114.33.

D:

10.63.112.0 has host bits set to zero, so it is the network ID rather than broadcast. The block ends at 10.63.115.255.

Question 67

At a hotel, the migration lead is planning an ordinary IPv4 LAN with mask /24. How many addresses can be assigned to hosts, excluding subnet and directed broadcast?

  1. 127 usable addresses
  2. 254 usable addresses
  3. 128 usable addresses
  4. 256 usable addresses

Explanation

Correct Answer

B:

A /24 subnet has 8 host bits, or 256 total IPv4 addresses; excluding network and broadcast leaves 254 usable host addresses. This is the traditional LAN-host count.

Incorrect Answers

A:

This count does not follow the /24 host-bit calculation; the correct operation is 2^(32-24) - 2 = 254. Subnet capacity should be validated against required growth.

C:

128 corresponds to splitting address space rather than counting both usable host endpoints in a /24 subnet. The actual block has 256 total addresses.

D:

256 includes the network and directed broadcast addresses. Ordinary IPv4 LAN host assignment excludes both endpoints.

Question 68

At a supply depot, the on-call technician needs a valid unicast gateway address in subnet 172.20.112.128/25. Which proposed IPv4 address is usable without using its network or broadcast address?

  1. 172.20.112.128
  2. 172.20.112.255
  3. 172.20.113.0
  4. 172.20.112.186

Explanation

Correct Answer

D:

172.20.112.186 falls strictly between 172.20.112.128 and 172.20.112.255; it is a valid host inside 172.20.112.128/25. That meets the requested gateway address constraint.

Incorrect Answers

A:

172.20.112.128 is the all-zero host-bit network address for 172.20.112.128/25, not a normal interface IP on this LAN.

B:

172.20.112.255 is the all-one host-bit directed broadcast for 172.20.112.128/25; using it as the gateway would conflict with broadcast behavior.

C:

172.20.113.0 is beyond the upper boundary of 172.20.112.128/25. Even though it looks adjacent, it belongs to the next subnet.

Question 69

At a distribution center, the on-call technician is configuring a Cisco interface in a /27 IPv4 network. Which dotted-decimal mask matches the given prefix?

  1. 255.255.255.248
  2. 255.255.0.0
  3. 255.255.255.240
  4. 255.255.255.224

Explanation

Correct Answer

D:

Prefix /27 sets 27 leading one bits, producing dotted mask 255.255.255.224. The remaining 5 bits define host numbering.

Incorrect Answers

A:

Mask 255.255.255.248 represents /29, not /27. Counting contiguous one bits gives the distinction.

B:

Mask 255.255.0.0 represents /16, not /27. Counting contiguous one bits gives the distinction.

C:

Mask 255.255.255.240 represents /28, not /27. Counting contiguous one bits gives the distinction.

Question 70

At a biotech lab, an implementation partner needs a single IPv4 subnet for 252 devices with no extra reserve requirement. Which mask is the smallest address block that can hold those devices?

  1. /26 (62 usable hosts)
  2. /25 (126 usable hosts)
  3. /23 (510 usable hosts)
  4. /24 (254 usable hosts)

Explanation

Correct Answer

D:

A /24 block offers 254 usable addresses, meeting the 252-host requirement with the smallest fitting normal IPv4 LAN block. It leaves 2 addresses for immediate growth.

Incorrect Answers

A:

This option fails the smallest-fitting-block criterion or has unsuitable capacity. Compare each prefix using 2^(32-p)-2 rather than treating larger prefix numbers as larger subnets.

B:

A /25 block offers only 126 usable hosts, less than the 252 required. Using the next longer mask would exhaust host capacity.

C:

A /23 block is larger than necessary for 252 endpoints; it consumes extra addresses even though a /24 block meets the stated limit.

Cisco Certified Network Associate (CCNA) (200-301) Practice Tests

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